Reactant  engrossment and Rate of Reaction    Aim:   See   scallywagboy 82 Exploring  chemistry Stage 2    Equipment:   See page 82 Exploring  chemical science Stage 2     affair:   See page 82 Exploring Chemistry Stage 2    Discussion:       Study of rate of  response  betwixt  atomic number 11 Thiosulfate and HCl, the rate is slower when diluted because the water particles  tie the  atomic number 11 thiosulfate particles to become more dispersed and so  in that  wish are less successful collisions at their activation  muscularity  significance it takes  long-term for the  entropy particles to be produced and thus it takes longer for the  issue to turn cloudy.    Safety:       Hydrochloric acid   sulphur dioxide (produced in this chemical reaction  if asthmatic then keep your distance)    Observations:   Before  essay: The  atomic number 11 thiosulphate was a  pallid solution. The hydrochloric acid was also a colourless solution.  During Experiment: The sodium thiosulphate reacted w   ith the hydrocloric acid to make a reaction mixture that  embark ons more cloudy as  yellow-bellied sulphur is  create  After Experiment:   The sodium thiosulphate and hydrochloric acid has reacted and  make a yellow substance (sulphur dioxide).    Results:    Vol of 0.25  gram  moleecule/L Na2S2O3  (mL)  Vol of water system added (mL)  Total Vol after adding and mixing 5 mL HCl  Concentration of   Na2S2O3 on mixing (mol/L)  Time for  brush to disappear (s)      1      Time  (s-1)  45  0  50  0.225  22  0.045  35  10  50  0.175  27  0.037  25  20  50  0.125  34  0.029  15  30  50  0.075  49  0.020  5  40  50  0.025  328  0.

00309    Reaction:    sodium thiosulp!   hate »» Sulphur + Sodium Chloride + Sulphur Dioxide + water system     NA2S2O3 + 2HCL »» S + 2NaCl + SO2 + H2O     (aq) + (aq) »» (s) + (aq) + (g) + (l)    Calculations:                      (C)(V)= (C)(V)             (1.25)(45) = (C)(50)                                C =   (0.25)(45)                                                (50)                                C = 11.25                                            50                               C = 0.225 mol/L    Conclusion:    As the concentration of Sodium...If you want to get a full essay, order it on our website: OrderCustomPaper.comIf you want to get a full essay, visit our page: 
write my paper   
No comments:
Post a Comment